can anyone explain a Algebra problem to me? (3Sqrt7-3sqrt3)^2
I just need to know how the steps to solve it
thanks Night watcher
\[(3\sqrt{7}-3\sqrt{3})^{2}\]
thanks you so much I just need to know how to do the problem like the formula or something
@zepdrix
Simply this one (3√7) Then simplify this one (3√3) Subtract both answers Then square it
3sqrt7 and 3sqrt3 squared is how to do it
?
what do i subtract
You can find this symbol √ on a calculator. so first type 3 times 7 then hit this button √. After you did that you simplified the first one.
Then do the same for the second one
\[(a+b)^2=(a+b)(a+b)=a^2+b^2+2ab\]
i am stil lost hold on
Then you'll subtract both of them answers and square them.
hold on I am lost so srry. Let me catch up
so you take the (3sqrt7-3sqrt3)^2 converts to 3sqrt7 and 3sqrt3 then I have to subtract what then square what
@amistre64 can u help
@Night-Watcher
i did help .... use the formula.
ok I am trying. so you take the (3sqrt7-3sqrt3)^2 converts to 3sqrt7 and 3sqrt3 then I have to subtract what then square what is this part right @amistre64
i would not do that ...
i would do:\[(a+b)=a^2+b^2+2ab\]
why?
sqrt7 and sqrt3 are irrational numbers that have no exact decimal forms to play with.
ok so that would be umm 3sqrt7+3sqrt3 is that part corrrect
sorry I am horrible at Algebra
I am trying hard but my math teacher explains it way to quick and complexx
\[(~\underbrace{3\sqrt7}_a~+~\underbrace{(-3\sqrt3)}_b~)^2\]
omg i have that part on paper but i thought it was wrong hold on
\[(a+b)=a^2+b^2+2ab\] \[(3\sqrt7-3\sqrt3)=(3\sqrt7)^2+(-3\sqrt3)^2+2(3\sqrt7)(-3\sqrt3)\]
thanks so much i got it Thanks so very very much
good luck
thanks I fanned u and medaled u
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