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Mathematics 16 Online
OpenStudy (anonymous):

How do you simplify a trigonometric expression?

OpenStudy (phebe):

GCG nd divide i think

OpenStudy (phebe):

i meant GCF

OpenStudy (phebe):

well its lik factor it nd order it k

OpenStudy (anonymous):

do you have an example?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

sin^2x /(1 + cosx) = ? sin^2x /(1 + cosx) = (1 - cos^2x)/(1 + cosx) = (1 - cosx) (1 + cosx)/(1 + cosx) = 1 - cosx

OpenStudy (anonymous):

I just need to know in words

OpenStudy (anonymous):

its easier if i show you mathematically though

OpenStudy (anonymous):

you're a 97 liner too huh

OpenStudy (anonymous):

The simplify(expr,trig) calling sequence simplifies trigonometric expressions by applying the trigonometric identities sin(x)^2+cos(x)^2 = 1 and cosh(x)^2-sinh(x)^2 = 1. • If the input is a polynomial in sin(x) and cos(x) then simplify/trig factors out powers of sin(x) and cos(x) and apply the identity sin(x)^2+cos(x)^2 = 1 to what is left so that the degree of what is left in sin(x) is at most 1. Thus the result is of the form: sin(x)^i*cos(x)^j*(A*sin(x)+B) where A and B are polynomials in cos(x). If the input is a polynomial in sinh(x) and cosh(x) then simplify/trig yields a similar result using the identity cosh(x)^2-sinh(x)^2 = 1. • To apply the identity to reduce the polynomial so that the degree in sin(x) is at most 1, use the command simplify(expr, {sin(x)^2+cos(x)^2-1}, [sin(x)]) • If the input involves multiple angles that are integer multiples of each other, for example, sin(x), sin(2*x), and cos((1/2)*x) then the trigonometric functions are expressed in terms of a common angle, in this case (1/2)*x. • If the input is a rational expression in sin(x) and cos(x) then an algorithm is used to put it in the form N/D and reduce N and D to lowest terms such that the total degree of the numerator N (in sin(x) and cos(x)) plus the total degree of the denominator is minimized. In particular, any common factor between N and D has been cancelled out.

OpenStudy (anonymous):

where did u get that from?

OpenStudy (anonymous):

damn...

OpenStudy (anonymous):

probably google

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

but thanks for searching.. i guess!

OpenStudy (anonymous):

u a 97 liner jelia?

OpenStudy (anonymous):

well obvioulsy no one else was gonna answer and they were wasting your time

OpenStudy (anonymous):

@hns109 could you simplify your answer? Im truly a dumba... lol

OpenStudy (anonymous):

ouch hns109

OpenStudy (anonymous):

lol i couldve did what he did! search online and copy and paste lol

OpenStudy (anonymous):

yeah haha

OpenStudy (anonymous):

can't wait to be done with math. last year of it lol

OpenStudy (anonymous):

let me see if i can win your heart through math

OpenStudy (anonymous):

thanks for the help sorta XD ill find something lol

OpenStudy (anonymous):

math finals in 2 days

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