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find the work in ft-lbs required to compress a spring from 1 ft shorter than its natural length to 2 ft shorter than its natural length if we exert a force given by f(x)=10x where x is the number of feet the spring has been compressed
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@sleepyhead314
so if that other formula doesn't work for this one then i have one more we learned
it's like that other one right? so W = integral from (smaller ft) to (bigger ft) of (equation) dx
k wait
15?
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that's what I got but I'm debating with myself of whether or not compressing it would mean the length would be negative? :/
:o
15
yeah :P that'd be it
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