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Mathematics 20 Online
OpenStudy (lovelyharmonics):

dot product

OpenStudy (lovelyharmonics):

Find the dot product, a • b. a = 6i + 5j, b = -5i + 4j

OpenStudy (anonymous):

( 6i + 5j)(-5i + 4j) use an expansion. Just curious if "i" is just a variable, or an imaginary...

OpenStudy (lovelyharmonics):

probably imaginary... but idk considering j is in there too .-.

geerky42 (geerky42):

Are you saying we have to use FOIL? I don't think it's how it works... @GABI_J

OpenStudy (anonymous):

No, I am saying just to factor it out... I am not that dumb;)

geerky42 (geerky42):

factor what out? can you be more clarification on that?

OpenStudy (lovelyharmonics):

.-. im so confused.... so if i foil it i get 10j^2 -ji +30 right .-. or am i suppose to get i+9j?

OpenStudy (anonymous):

trying to sound smart? Okay:)

geerky42 (geerky42):

I don't think you really know what dot product is.

OpenStudy (lovelyharmonics):

.-. well if i factor it i get i+9j and you both said factor so wtf .-.

geerky42 (geerky42):

Just ignore GABI_J, You simply multiply first numbers in vectors, then same thing to second numbers, then add them together. For example: ( 1i + 2j ) • ( 3i + 4j ) = <1, 2>•<3, 4> = (1)(3) + (2)(4) does that makes sense? @lovelyharmonics

OpenStudy (lovelyharmonics):

.-. i dont get it

geerky42 (geerky42):

6i + 5j and -5i + 4j looks little messy, so let clean it a little bit: <6, 5> and <-5, 4> Now you just multiply first number in first vector by first number in second vector Like this: (6)(-5) Do same to second numbers in both vector You should get (5)(4) Then you add them together: (6)(-5) + (5)(4) does that help?

geerky42 (geerky42):

Basically let say you have <a,b>•<c,d>. <a,b>•<c,d> = ac + bd

geerky42 (geerky42):

does that help you??

OpenStudy (lovelyharmonics):

okay so -30 +20=10

OpenStudy (lovelyharmonics):

*-10

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