Question

METAL WILL BE AWARDED

Write down the next three rows to continue this sequence of equations.
1 = 1 = 1^3
3 + 5 = 8 = 2^3
7 + 9 + 11 = 27 = 3^3
13 + 15 + 17 + 19 = 64 = 4^3

Answer 1

Well we at least know that based on the given pattern, it is obvious that the next three rows will be
5^3
6^3
7^3

right?

Answer 2

Yes but there is more

Answer 3

Of course. The next step is so evaluate 5^3, 6^3, and 7^3

Answer 4

In other words, find the integer values of each.

Answer 5

I think there's more to solve it like the addition to it

Answer 6

Yes, but @LeadSkills, do you know how Open Study works? The goal here is to "guide" not just give the answer all at once.

Answer 7

I see.

Answer 8

I am thinking of this problem and I see a pattern with the numbers and the exponents

Answer 9

Great. Would you mind posting what you believe the next three rows are?

Answer 10

Well numbers are going down obvious so the 1st one is adding 4

Answer 11

Hint:
Notice that the sums on each row are consecutive odd integers:
{1, 3, 5, 7, 9, 11, 13, 15, 17, 19...}

Answer 12

Now I understand

Answer 13

The best way to demonstrate that you understand is to post what you believe are the next three rows.

Answer 14

Okay I will Hero

Answer 15

1 = 1 = 13
3 + 5 = 8 = 23
7 + 9 + 11 = 27 = 33
13 + 15 + 17 + 19 = 64 = 43
21 + 23 + 25 + 27 + 29 = 125 = 53
31 + 33 + 35+ 37 + 39 + 41 = 216 = 63
43+ 45 + 47 + 49+ 51+53 + 55 = 343 = 73

Answer 16

@Hero 1 = 1 = 13
3 + 5 = 8 = 23
7 + 9 + 11 = 27 = 33
13 + 15 + 17 + 19 = 64 = 43
21 + 23 + 25 + 27 + 29 = 125 = 53
31 + 33 + 35+ 37 + 39 + 41 = 216 = 63
43+ 45 + 47 + 49+ 51+53 + 55 = 343 = 73

Answer 17

I believe you have it. The only discrepancy seems to be that you left out the carets for
1^3, 2^3, 3^3, etc...

Answer 18

Ye It didnt transfer in open study

Answer 19

Great job though.

Answer 20

I have and other question to solve and I want to try to solve it.

Answer 21

A train can hold 78 passengers. The train starts out empty and picks up 1 passenger at the first stop, 2 passengers and the second stop, 3 passengers at the third stop, and so forth. After how many stops will the train be full?

Answer 22

Hold on