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Which of the following expressions is equivalent to |x – 2| < 3? A. –3 > x – 2 < 3 B. –3 < x – 2 < 3 C. x – 2 < 3 and x – 2 < –3 D. x – 2 < 3 or x – 2 < –3
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the correct answer is B....you know how it is solved??
not really. this has been pretty hard for me
look why it is option B...i'll explain... when x-2 is greater than -3, i.e., -3<x-2, then x-2 has any values starting from -2.999.. so modulus of x-2 will always be less than 3. again when it'll be less than 3, i.e., x-2<3, then all values of x-2 will be less than 3. so mod x-2 will always be less than 3 within -3 and 3.
ok that actually helped, thank you at first i didnt get it. thanks man
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