solve the triangle A=46(degrees) ,a=31 ,b=27 Please help, i keep getting the wrong answers
IDK I got 2 but that's
the options are B = 38.8°, C = 115.2°, c ≈ 34.3 B = 38.8°, C = 95.2°, c ≈ 25.7 B = 38.8°, C = 95.2°, c ≈ 42.9 Cannot be solved
I'll try it again sorry
no problem thanks
oh okay sorry
did you get an answer yet?
c=42.91
cosA=(b^2+c^2 - a^2)/(1*bc)
yeah i tried the equation and i would get like 0.75. But thanks :)
/2bc not /1bc hope it helps
dunno i used that equation but my calculator gave me 42.91729 my pleasure
* A = 46 degrees If it's a right triangle, use a^2+b^2=c^2, or a trig function. If it's obtuse, use a trig function, or law of sines/cosines 2 possible triangles could be formed. Basically imagine side a intersecting side c at a different point. In either triangle Angle A is still 46° and side a = 31 and side b = 27.
IDK, I hope this stuff helps
sorry I tried
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