Question

I have two problems I keep getting wrong on my calculus test. Can someone help me?

Answer 1

\[\int\limits_{a}^{b}k(x)=k(b)-k(a)=L\]
k(a)=k(b)-L
now
\[\int\limits_{b}^{c}k(x)=k(c)-k(b)=M\]
k(b)=k(c)-M
like this

Answer 2

\[\int\limits_{0}^{c}k(x)=k(c)-k(0)=N\]

Answer 3

so
from those three we are getting
k(a)=k(b)-L
k(b)=k(c)-M
and k(c)=N+k(0)
so
\[\int\limits_{0}^{a}k(x)dx=k(a)-k(0)=k(b)-L-k(0)=k(c)-M-L-k(0)=N+k(0)-M-L-k(0)=N-M-L\]

Answer 4

do u get it @watermelon16

Answer 5

They have it in subtraction of letters. like
L - M - N
L + M - N
N - L - M
N + L + M
Would it be the second one?

Answer 6

(N-M-L) thats the answer

Answer 7

Okay, explain to me how you know. Still a little confused.

Answer 8

k(a)=k(b)-L
k(b)=k(c)-M
and k(c)=N+k(0)
do u get it so far?

Answer 9

oh I see.

Answer 10

so far ok?