Question

, how would you transform f(x) = 2 sin(2x - π) + 3 into a cosine function in the form f(x) = a cos(bx - c) + d?

Answer 1

by a phase shift of course ...

Answer 2

sin(n) = cos(n-pi/2) seems familiar

Answer 3

maybe +pi/2

Answer 4

sin(pi/2) = 1
cos(pi/2-pi/2) = 1

nah, its a minus pi/2