Help Please
A right triangle has base (x - 6) units and height (6x - 12) units.
Part A: What is the square of the length of the hypotenuse of the triangle? Show your work.
Part B: What is the area of the triangle?
Part C: Using the solution obtained in Part B, explain the closure property of multiplication of polynomials.
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OpenStudy (anonymous):
im guessing you have to square (x-6)^2 and (6x-12)^2
OpenStudy (anonymous):
am i right
OpenStudy (anonymous):
and then for part b i solve it right
OpenStudy (anonymous):
tell me if im wrong please
OpenStudy (anonymous):
anyone
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OpenStudy (anonymous):
know
OpenStudy (anonymous):
help please
OpenStudy (anonymous):
Part A wants the length of the hypotenuse in squared form. Do you know how to find the length of the hypotenuse when you know the length of the other two sides?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
sorry
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OpenStudy (imstuck):
Yes, you're right. For part B, the answer I get it 6 *sqrt (x-2)^2 + (x-6)^2 = c
OpenStudy (anonymous):
|dw:1400813355916:dw|
\[a^2 + b^2 = c^2\]
OpenStudy (anonymous):
We need c^2
OpenStudy (anonymous):
ok how do i do that
OpenStudy (anonymous):
Ok, well in this case we know the value of the base and the height, so it would look like this:
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OpenStudy (anonymous):
|dw:1400813465011:dw|
OpenStudy (anonymous):
im confused
OpenStudy (anonymous):
i dont see anything
OpenStudy (anonymous):
Ok, do you know what a hypotenuse of a triangle is?
OpenStudy (anonymous):
no
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OpenStudy (anonymous):
It's the longest side of a right triangle. It's also a right triangle because it has a 90 degree angle.
OpenStudy (anonymous):
ok so do i have to take the height and square it
OpenStudy (anonymous):
so (6x-12)^2
OpenStudy (anonymous):
\[a^2 + b^2 = c^2\]
We have to square the height, and add it to the square of the base.
OpenStudy (anonymous):
so (x-6)^2+(6x-12)^2
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OpenStudy (anonymous):
Yep, now when you simplify that don't remove the square.
OpenStudy (anonymous):
ok so how do i simplify
OpenStudy (anonymous):
sorry ive been testing for 5 hours my brains kind of fried
OpenStudy (anonymous):
so do i do the foil method
OpenStudy (anonymous):
You would use the foil method if this was a quadratic we were going to simplify, but that's actually completely unrelated
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OpenStudy (anonymous):
\[(x - 6)^2 + (6x - 12)^2 = c^2\]
First we should simplify the x values
OpenStudy (anonymous):
What is x + 6x?
OpenStudy (anonymous):
6x^2
OpenStudy (anonymous):
That would be 6x * x
OpenStudy (anonymous):
\[x + x = 2x\]
\[x * x = x^2\]
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OpenStudy (anonymous):
oh then im not sure sorry
OpenStudy (anonymous):
is it 7x or 8x
OpenStudy (anonymous):
for x + 6x, remember that there's actually a hidden 1 beside the x.
1x + 6x = 7x
OpenStudy (anonymous):
oh ok thanks
OpenStudy (anonymous):
Now -6 - 12 simplified is
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OpenStudy (anonymous):
-18
OpenStudy (anonymous):
so for part A:
\[c = (7x - 18)^2\]
OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
so what do i do for b
OpenStudy (anonymous):
For part B we need the area of the triangle
The formula for the area of a right triangle is:
\[\frac{ ab }{ 2 }\]
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OpenStudy (anonymous):
And again:
A = x - 6
B = 6x - 12
OpenStudy (anonymous):
ok so i have to solve for x
OpenStudy (anonymous):
Yep, I think I can see some foiling up ahead
OpenStudy (anonymous):
ok so what do i have to foil
OpenStudy (anonymous):
oh wait never mind its A = x - 6
B = 6x - 12 that i have to foil right
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