The coordinate plane below represents a city. Points A through F are schools in the city. Part A: Using the graph above, create a system of inequalities that only contain points B and C in the overlapping shaded regions. Explain how the lines will be graphed and shaded on the coordinate grid above. Part B: Explain how to verify that the points B and C are solutions to the system of inequalities created in Part A. Part C: Lisa can only attend a school in her designated zone. Lisa's zone is defined by y > 2x + 5. Explain how you can identify the schools that Lisa is allowed to attend.
I'm doing that same exam right now.
really can you help??
That's what was just going to ask you I'm not sure but I am working on it.
Where is the shaded region?
i have no idea. i guess its F it looks shaded or maybe the negative is the shaded.
No it should be an obvious shaded region
it should be noticeable in the problem. This is all the information you have?
yes it is
Ok I may have an idea then
i guess from the way the question sounds b and c are the shaded regions
what's your idea?
I'm not sure now. I think it wants to only include the first quadrant within the cartesian. Which would be x>0, y > 0. I'm not sure how else you would do it (part A)
do you have an answer bank? There could be many ways to do this.
yes i have a blank answer
ok so you cannot choose from a list?
nope
Part B the region should be shaded for all positive values of x and y
okay
For part C she must attend schools D and E
This is because you know the y-intercept must be at 5 and the slope is 2 according to the inequality y > 2x+5
oh okay thank you so much!!
Since y is greater than, that means that the region is shaded where the values are above the line (regions D and E)
You can make up an equality for A and B like part C
inequality*
for example you could use the same inequality as part C with a slope of -2 and a < sign which works for points A and B
so part A I could make up the inequality y<-2x+5
Cool that works
Yeah it is somewhat of a weird question(s) but I think that will work for what it is asking
It really was, i mean no one could answer it.
was that answer correct? @meilendurcer
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