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How many 2-digit numbers can be formed using only the digits 2, 3, 5, and 6, if the digits are not be repeated within a number? Please Help!!! This is a Permutation
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You have a permutation without repetition so you want which formula do you know can help you solve for this?
uh i don't know...
well for the 1st digit you have 4 choices... and the 2nd digit there will be 3 choices.. so by the fundemental theorem of counting you have 4 x 3 ways
I know that formula but i need to figure out how to make 2 digit numbers
with them
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well you don't need a formula... for this question you just need to know the number of choices at each stage,, and multiply the number of choices...
|dw:1400824332321:dw|
ok thank you so much!
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