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solve the triangle. B = 36°, a = 41, c = 17
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well you can draw a diagram |dw:1400824683982:dw| now it depends on what you need to find...? and angle A or C or side b
can you walk me through this please
im suffering
ok... so lets start by finding b... you need to rule of cosines \[b^2 = 17^2 + 41^2 - 2 \times 17 \times 41 \times \cos(36)\]
okay i'm tryiing to work it out hold on
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i got 289+1681x1394 cos 36
@campbell_st
b=465?
i mean 21.5
@campbell_st
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well I got 29.02 I've checked it and think I'm right... so next to find an angle... say angle A use the law of sines \[\frac{\sin(A)}{41} = \frac{\sin(36)}{29.02}\] now solve for A
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