The graph below shows a line segment AB: Which of the following equations best represents the line segment AB? y = -3x + 2 y = -2x + 1 y = -3x - 2 y = -2x - 1
@kx2bay
@ganeshie8 @phi
You want to find the line segment in the form of \[y = mx + b\] Where m is the slope\[m = \frac{ \Delta Y }{ \Delta X }= \frac{ (Y_2-Y_1) }{ (X_2-X_1) }\]
i don't understand
B = the y-intercept
ok and A is x right
Use 2 point on your line (preferably the 2 end points) and solve for the slope and then find where the goes through the y-axis (0, y) )and the y value will be your b
slowly im understaning
5,-4
Those are 2 Y-axis coordinates.
so -1?
it's below 5 but not ending at -1
Point A will be (X2,Y2) and point B will be (X1,Y1) or the opposite way around its up to you
use these coordinates : A = (-1, 5) B = (2, -4)
try to find slope(\(m\)) using the slope formula
is it D?
that's the on;y one that seems logical to me.
nope, did u find the slope yet ?
how do i find the slope?
You can actually tell right away that it is not D, find the slope or the y-intercept and you will find your answer
The y-intercept is at 2, so in the equation \[y=mx+b\]b=2, which gives you\[y=mx+2\]The line passes through (1, -1), so plug in (1, -1) into the equation above to get the value of 'm'
you got two points A and B, you can use the slope formula : http://www.algebra-class.com/image-files/slope-formula-2.gif
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