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Mathematics 21 Online
OpenStudy (meilendurcer):

The graph below shows a line segment AB: Which of the following equations best represents the line segment AB? y = -3x + 2 y = -2x + 1 y = -3x - 2 y = -2x - 1

OpenStudy (meilendurcer):

OpenStudy (meilendurcer):

@kx2bay

OpenStudy (meilendurcer):

@ganeshie8 @phi

OpenStudy (anonymous):

You want to find the line segment in the form of \[y = mx + b\] Where m is the slope\[m = \frac{ \Delta Y }{ \Delta X }= \frac{ (Y_2-Y_1) }{ (X_2-X_1) }\]

OpenStudy (meilendurcer):

i don't understand

OpenStudy (anonymous):

B = the y-intercept

OpenStudy (meilendurcer):

ok and A is x right

OpenStudy (anonymous):

Use 2 point on your line (preferably the 2 end points) and solve for the slope and then find where the goes through the y-axis (0, y) )and the y value will be your b

OpenStudy (meilendurcer):

slowly im understaning

OpenStudy (meilendurcer):

5,-4

OpenStudy (anonymous):

Those are 2 Y-axis coordinates.

OpenStudy (meilendurcer):

so -1?

OpenStudy (meilendurcer):

it's below 5 but not ending at -1

OpenStudy (anonymous):

Point A will be (X2,Y2) and point B will be (X1,Y1) or the opposite way around its up to you

ganeshie8 (ganeshie8):

use these coordinates : A = (-1, 5) B = (2, -4)

ganeshie8 (ganeshie8):

try to find slope(\(m\)) using the slope formula

OpenStudy (meilendurcer):

is it D?

OpenStudy (meilendurcer):

that's the on;y one that seems logical to me.

ganeshie8 (ganeshie8):

nope, did u find the slope yet ?

OpenStudy (meilendurcer):

how do i find the slope?

OpenStudy (anonymous):

You can actually tell right away that it is not D, find the slope or the y-intercept and you will find your answer

OpenStudy (anonymous):

The y-intercept is at 2, so in the equation \[y=mx+b\]b=2, which gives you\[y=mx+2\]The line passes through (1, -1), so plug in (1, -1) into the equation above to get the value of 'm'

ganeshie8 (ganeshie8):

you got two points A and B, you can use the slope formula : http://www.algebra-class.com/image-files/slope-formula-2.gif

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