Question

Please help me out...?

Answer 1

Convert it into a log.

Answer 2

So 5^26?

Answer 3

\(\LARGE a^x=b <===> log_{a}~b=x\)

Answer 4

Ohhh... so 5^-26?

Answer 5

Uhm, no >_<

How are you arriving at those answers?

Answer 6

A=5 B=26?

Answer 7

Right.. now put it into the log equation.

Answer 8

log 5 26=x

Answer 9

There ya go, now plug that into a calculator and you will get x.

Answer 10

That's what idk how to do...

Answer 11

If you can't type in \(\Large log_{5}~26\)
Then use the change of base formula.

Answer 12

\[\Large log_{5}~26=\frac{log~26}{log~5}\]

Answer 13

Those log's have a base of 10 btw, which on the calculator is already programmed,