Question

Find the area of a regular pentagon with a side length of 14 and an apothem of 22. medal an fan

Answer 1

@phi

Answer 2

@ganeshie8

Answer 3

@mwhit2101 @sarah786 @Warriorz13 @CrazyCountryGirl @lovelyr0se @ikatouni

Answer 4

@mathslover

Answer 5

Here hun try this
http://www.mathopenref.com/apothem.html

Answer 6

what do i do with this?

Answer 7

IDK
I think it kinda like a calculator

Answer 8

humm ok

Answer 9

what do i do for n

Answer 10

@Warriorz13

Answer 11

Let n= the number of sides of a regular polygon
s=the length of each side.
A= the area of the n-gon

Divide the n-gon into n congruent isosceles triangles. We'll do it here for a 4-gon, where each side is 6cm.

Reply Using Drawing


Now divide the iso triangles into congruent right triangles.

3
3
Reply Using Drawing


Figure out the angle at the middle of each right triangle.


3
x
Reply Using Drawing


x = 360/(n/2)
= 180/n

using trig:

tan(x) = (s/2)/h

or h = s / 2tan(180/n)

the area of one of the right triangles is thus

a= (1/2)(s/2)(s / (2tan(180/n)))

a= s^2 / (8tan(180/n))

and the area of the n-gon is 2*n*a, so

A= s^2 / (4*tan(180/n))


I would suggest working through it with the square (n=4, s=6cm) if you are still having difficulty.


Good Luck

Answer 12

750?