Question

Find the equation of a circle with a center at (-1, 5) and a point on the circle is (4, 4).


(x - 4)2 + (y - 4)2 = √26
(x - 4)2 + (y - 4)2 = 26
(x + 1)2 + (y - 5)2 = 26
(x + 1)2 + (y - 5)2 = √26

Answer 1

@minoz

Answer 2

centre would be
what is in the brackets
i.e.,(a,b) is centre implies eqn should contain (x-a) and (y-b)
substitute (4,4) in the eqn and ans shoulb be zero

Answer 3

(x+1)^2+(y-5)^2=26 do yo understand?

Answer 4

sorta

Answer 5

yeah I got it.