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verify this identity (a+b+c)^2= a^2+b^2+c^2+2ab+2bc+2ca
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It's always true.
just multiply (a+b+c)*(a+b+c)= and just start solving and you get there, it's very simple
@arbershabani97 is right!
\[(\overline{a + b} + c)^2 = (a + b)^2 + c^2 + 2(a + b)(c)\]
same thing lol :P
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\[(a+b+c)^{2}=a(a+b+c)+b(a+b+c)+c(a+b+c)\] Then distribute each one again and simplify :)
is latex coding down? or just my end?
Just you.
refresh helped ....
ahem staph notifications lol :P
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