Which function has the most x-intercepts?
@Hero can you explain to me what steps I take to solve this"?
One step would be to familiarize yourself with the max number of zeroes a cubic function could possibly have.
f(x) obviously has four zeroes. Can h(x) have more zeroes that that?
Only 1
A cubic function can have up to three zeroes right?
Oh wait yes? and a squard one can have up to two
I don't know?
I mean f(x) already has four zeroes. So what do you think this means?
h(x) has more
But h(x) is the cubic function, right? A cubic function can only have up to 3 real zeroes right?
(h)x has less
f(x) could be a quadratic equation then? I am not sure
@Hero
Seriously if nobody is going to answer
How many zeroes does f(x) have?
4
How many does g(x) have?
2 or 3 I am not sure
It only has two considering the restraints from x = 0 to \(x = 2\pi\)
Okay so how do I solve this?
Here's the graph of h(x) https://www.desmos.com/calculator/gbaecbuhmm How many zeroes does it have?
3
Okay, so which function has the most zeroes?
So f(x) would be correct answer right?
Hello?
@Hero
Yes, f(x) is correct.
Ty, f(x) was correct. (Just took the test :)
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