Question

Trigonometry: check my work?

and I need help to find sec theta?

Answer 1

sec(theta) = 1/cos(theta)

since cos(theta) = adj/hyp, this means sec(theta) = hyp/adj

you take the reciprocal of cos(theta) to find sec(theta)

Answer 2

also, your answer of sin(theta) = -3/4 is incorrect

your triangle should be labeled like this

Answer 3

would sinθ be
4/H

5^2+y^2=4^2

25+y^2=16
y= -9

-4/3 <-

Answer 4

5^2+y^2=4^2 is the incorrect equation

Answer 5

it should be 5^2+4^2 = y^2

y is the hypotenuse

Answer 6

-4/41 ?

Answer 7

not quite

Answer 8

What do I do?

Answer 9

what is 5^2+4^2 equal to?

Answer 10

41

Answer 11

41

Answer 12

mathman123 please don't give out the answer

Answer 13

sry

Answer 14

5^2+4^2 = y^2

y^2 = 41

y = ???

Answer 15

20.5?

Answer 16

y^2 means y squared

not y times 2

Answer 17

Im confused do i find √41?

Answer 18

it's just \[\Large \sqrt{41}\]