When -4(2x^2-3x-12) is simplified, what is the value of the constant term? A. -8 B.12 C.48 D.52
Follow the Order of Operations Parentheses Exponents Multiplication Division Addition Subtraction
distribute the -4, see what you get
I got -32x-12x-48 Do I add -32 and -12x
If they are like terms, yes.
-32x?
Yes I go that
\(\bf {\color{brown}{ -4}}(2x^2-3x-12)\implies ({\color{brown}{ -4}}\cdot 2x^2)+({\color{brown}{ -4}}\cdot -3x)+({\color{brown}{ -4}}-12)\)
hmm missed a multiplication bit \(\bf {\color{brown}{ -4}}(2x^2-3x-12)\implies ({\color{brown}{ -4}}\cdot 2x^2)+({\color{brown}{ -4}}\cdot -3x)+({\color{brown}{ -4}}\cdot -12)\) but anyhow, you wouldn't get a 32x either way, and the in the "constant" is the one without a variable
The answer is d?
hmm dunno... what did you get for the constant?
Well I did what you told me to do in the last status and I got. 52
What would be the constant term? Well what is a constant term?
a constant term is a number with no variable, which is why it is constant with no variable that can be any number in the universe
I tnk the answer is d cause that's what I got as my final answer
??
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