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lim(x->2) f(x)=4 lim(x->2) g(x)=2 lim(x->2) h(x)=0 what would lim(x->2) (g(x)h(x))/f(x)
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i tried working this out and i got (-2)(0)/4
wouldnt it be 0?
You're right ! you're using multiplication law for limits in the background. look it up : http://www.math.oregonstate.edu/home/programs/undergrad/CalculusQuestStudyGuides/SandS/lHopital/limit_laws.html
thanks!
yw
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