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4^x - 2^x = 3 Solution? Is it unsolvable?
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It is solvable ,
Can you show the source of the question ( snapshot ) ?
\[\implies \left(2^x\right)^2 - (2^x) = 3\]
\[\implies (2^x)^2 - (2^x) = 3\]\[\implies (2^x)^2 - (2^x) - 3 =0\]Find the solutions of this quadratic. Ignore the negative solutions as \(2^x\) cannot be negative.
Tried using the quadratic formula. I ended up with (2^x +- 2^x * sqrt(3)) / 4^x = 0 and I cannot seem to get anywhere else from that. Also I have tried entering this into wolfram/mathway and it gives no solution or impossible solutions.
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If you use the hints provided by @ParthKohli then you should find a valid solution. It might help if you substituted: \(y=2^x\) and solved for \(y\) first.
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