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Can someone guide me through the steps of (3x-x^2)/(2x-2)? I understand the concept of polynomial long division, I am just confused on how to deal with the coefficient 2 on the 2x in the denominator.
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\[2(2-x+\frac{ 2 }{ x-1 })\]
Why is the 2 taken out of 2x-1?
It becomes simpler to solve
Oh... so you temporarily take it out, do the math, then add it back in to the final answer.
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exactly, a little tricky
Thanks!
you're welcome
Oh and sorry it should be 1/2 not 2 since it was on the denominator
so final equation is actually \[\frac{ 1 }{ 2 }(2-x+\frac{ 2 }{ x-1 })\]
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