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Solve x^2 + 27 = 0 and write factors. I got (x+9)(x+3) Is this one right?!?
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is \(\bf x^2\ or\ x^3?\)
squared
Aren't you missing your middle term?
Is it solve x^2+12x+27?
\(\bf x^2 + 27 = 0 \implies x^2=-27\implies x=\pm\sqrt{-27} \\ \quad \\ x=\pm\sqrt{27\cdot -1}\implies x=\pm\sqrt{27}\cdot \sqrt{-1} \\ \quad \\ x=\pm \sqrt{3^2\cdot 3}\cdot \sqrt{-1}\implies x=\pm 3\sqrt{3}\ i\)
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If not then ^^ that would make sense
No.. That's what on the paper.
well.... given +27.... it'd yield a negative -27 on the equation... maybe if you post a screenshot of the material
I'm scanning the sheet now.
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It's upside down... Sorry
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