Question

I'll post a picture of the problem in a sec
It's an SAT problem and it's a tricky question
the answer is C, but I don't know why I'm not getting that answer

Answer 1

Since the area of the circle is \(\large 9\pi \), this implies the radius is 3. So the height of the equilateral triangle is 6. Using the pythagorean theorem, the side of the triangle \(\large 4\sqrt{3} \). So area of the triangle = \(\frac{1}{2}(base)(height)=\frac{1}{2}(4\sqrt{3})(6)= \) ???

Answer 2

thank you very much, the mistake I did was that i found the radius and then the height of triangle, but randomly changed it to 2, so that was the mistake. Thanks