I have a quadratic eq. question: Which of the following is a solution of 2x2 = -3x - 5? a. x = -3 -7i over 4 b. x = 3 + 7i over 4 c. x = 3 - i sqrt 31 over 4 d. x = -3 + i sqrt 31 over 4
here agin a=+2 b=+3 and c=+5
check if you get d. x = -3 + i sqrt 31 over 4 after using quadratic formula..
so it got c. but it's because of the negative sign again
check if you get d. x = -3 + i sqrt 31 over 4 after using quadratic formula
check the sign of b
you have to make the 3x and the 5 positive right!
no not that..
to get it in the form of the quadratic equation? with zero on the other side?
yup 2x2 = -3x - 5 2x2 + 3x + 5 =0 now you compare it with standard quadratic..
ok yes it get this now! you're a great teacher! then it's just factoring it out. the sqrt's upset me lol!
sometimes it can be factored other times not..
so you just simplify as much as possible and that's your answer?
thanks again I am beginning to understand..
yw
but for ax^2+bx+c = 0 x= (-b - sqrt(b^2 -4ac))/(2a) , (-b + sqrt(b^2 -4ac))/(2a)
oh cool, yes I can see now! I am putting that in my notes now. You are super!
yw
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