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OpenStudy (anonymous):

Dogs,Households 0,1134 1,430 2,169 3,43 4,25 5,16

OpenStudy (anonymous):

anyone

OpenStudy (anonymous):

What is the question?

OpenStudy (anonymous):

Dogs,Households 0,1134 1,430 2,169 3,43 4,25 5,16

OpenStudy (anonymous):

x and p(x)

OpenStudy (anonymous):

x being the number of dogs and p(x) being the number of households?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

and what are you supposed to find? the equation for p(x)?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

and round to the nearest thousandth

OpenStudy (anonymous):

p(x) = 984.8143*0.4100^x not quite sure if that's the form you wanted it in.

OpenStudy (anonymous):

no thank you it have to be from 0 to 1 and u around to the nearest thousandth

OpenStudy (anonymous):

that makes no sense whatsoever. Maybe you should try posting the entire question all restrictions included.

OpenStudy (anonymous):

okay than u i will

OpenStudy (anonymous):

need yr help 5 5 3 3 2 2 2 4 find the range, sample variance and standard deviation

OpenStudy (dangerousjesse):

Do you know how to find the range if a set of numbers?

OpenStudy (anonymous):

yes

OpenStudy (dangerousjesse):

Then what's the range?

OpenStudy (anonymous):

1

OpenStudy (dangerousjesse):

Not quite.. You had the right idea, though. Rearrange all of the numbers so that they're in order from greatest to least.

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

the range is simply the smallest number in a series subtracted from the largest number in a series

OpenStudy (anonymous):

thank u

OpenStudy (anonymous):

about the sample variance

OpenStudy (dangerousjesse):

Yeah, I was getting to that part haha. Subtract the last number from the first number in your list and you should get the range. The variance is the average of the squared differences from the Mean. Standard deviation is the square root of the Variance.

OpenStudy (anonymous):

okay thank u so much

OpenStudy (dangerousjesse):

No problem.

OpenStudy (anonymous):

u there

OpenStudy (anonymous):

what is an advantage to using the range has a measure of variation ?

OpenStudy (dangerousjesse):

Mind rephrasing that?

OpenStudy (anonymous):

what is an advantage of using the range as a measure of variation

OpenStudy (dangerousjesse):

The range is the simplest measure of variation to find.

OpenStudy (anonymous):

my choice A) it uses all entries from the data set B) IT USES ONLY TWO ENTRIES FROM THE DATA SET C) it hard to compute

OpenStudy (anonymous):

u there

OpenStudy (dangerousjesse):

Yeah, it's A.

OpenStudy (anonymous):

okay thx what is the disadvantage

OpenStudy (anonymous):

same choice

OpenStudy (dangerousjesse):

Wait, it's B. Sorry haha. What are your choices?

OpenStudy (anonymous):

lol hahhaha

OpenStudy (anonymous):

thank u so much this homeowrk is killing me

OpenStudy (dangerousjesse):

No problem haha.

OpenStudy (anonymous):

hahhah thank god i find u

OpenStudy (anonymous):

predict the values of y for x=2 A) 57.1 B)48.2 C)63.0 D)NOT MEANINGFUL

OpenStudy (anonymous):

JESSE

OpenStudy (dangerousjesse):

o-o

OpenStudy (dangerousjesse):

Yes?

OpenStudy (anonymous):

0-0

OpenStudy (dangerousjesse):

Oh, it's D.

OpenStudy (anonymous):

ABOUT IF X=3.5

OpenStudy (dangerousjesse):

Still D haha.

OpenStudy (anonymous):

HAHHAAHA

OpenStudy (anonymous):

EVEN IS X=13

OpenStudy (dangerousjesse):

Still D :P

OpenStudy (anonymous):

HAHAHA

OpenStudy (anonymous):

THE FIRST QUESTION THAT I ASK U ABOUT THE RANGE, SAMPLE VARIANCE AND STANDARD DEVIATION IM STILL NOT DONE WITH IT I GOT THE RANGE 3 BUT I CANT FIND THE REST

OpenStudy (anonymous):

5 5 3 3 2 2 2 4

OpenStudy (anonymous):

JESSE

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