Question

Change ((-3sqrt3)/2, (3/2)) to polar coordinates?

Answer 1

R=x^2+y^2
Q=arc tan (y/x)
(X,y)=(p,q)

Answer 2

Sorry meant (r,q)

Answer 3

ok so what do i plug in for all of that?

Answer 4

Your values for x and y

Answer 5

R^2= (-3sqrt3/2)^2+(3/2)^2= (-3*3/4)+(9/4)=-9/4+9/4=0
Arc tan (-3sqrt3/2/(3/2)=arc tan (-sqrt3)

Answer 6

Q=2pi/3

Answer 7

ok thanx so much!!!

Answer 8

Answer (0,2pi/3)

Answer 9

I was working it through and checked here to ask if it was right but you wrote the same thing i got!

Answer 10

Awesome glad I could help