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A 6-m extension ladder leans against a vertical wall with its base 2m from the wall. How high up the wall does the top of the ladder reach? Round to the nearest tenth.
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just do Pythagorean theorem. x^2+2^2=6^2. can you solve for x?
Yeah the Pythagorean theorem. a^2 b^2 = c^2 like what Juicstice said.
*a^2 + b^2 = c^2 oops.
x^2+2^2=6^2 x^2+4=36 36-4=32 x^2=32 \[\sqrt{32}\] =5.6 x=6m
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not it would be 5.6
oh okay i thought i had to round it
yea, to the nearest tenth
alright, so 5.6 stays the same. ok so then what's the next step
you have it :).
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oh really?! lol im stupid i thought i had to find the perimeter or something
nope lolz
alrighty thank youuu
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