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Mathematics 12 Online
OpenStudy (anonymous):

I need some help with graphing logarithmic functions please!

OpenStudy (anonymous):

If you have ever swum in a pool and your eyes began to sting and turn red, you are aware of the effects on an incorrect pH level. The pH level measures the concentration of hydronium ions and can be modeled by the function p(t) = –log10 t. The variable t represents the amount of hydronium ions, and p(t) gives the resulting pH level. Water at 25 degrees Celsius has a pH of 7. Anything that has a pH lower than 7 is called acidic, while pH's above 7 are basic or alkaline. Seawater has a pH just over 8, while lemonade has a pH of approximately 3.

OpenStudy (anonymous):

1.Create a graph of the pH function. Locate on your graph where the pH value is 0 and where it is 1. You may need to zoom in on your graph.

OpenStudy (anonymous):

@Hero could you help me again please? I have all the info! lol

hero (hero):

So you have \(p(t) = -\log_{10}(x)\) and need to find where p(t) = 0 and p(t) = 1, right?

OpenStudy (anonymous):

Yes.

hero (hero):

Correction you have \(p(t) = -\log_{10}(t)\) right?

hero (hero):

What happens when t = 1 ?

OpenStudy (anonymous):

p(1)=-log10(1)?

hero (hero):

Yes, what result do you get for p(1)?

OpenStudy (anonymous):

I'm getting 0?

hero (hero):

Yes, correct. That's what we want, right?

hero (hero):

So far we figured out that p(1) = 0 right?

OpenStudy (anonymous):

Yes.

hero (hero):

Okay, now what happens when t = 0.1?

OpenStudy (anonymous):

I get 1! :D

hero (hero):

What happens when t = 0.01?

OpenStudy (anonymous):

But how would I graph this? and i'd get 2!

hero (hero):

Oh, looks like you found a way to find all the pH's

hero (hero):

You can graph it using this: https://www.desmos.com/calculator

OpenStudy (anonymous):

Thank you so much. :)

hero (hero):

You're welcome

OpenStudy (anonymous):

How can I give you a medal? lol

hero (hero):

Looks like you figured it out

OpenStudy (anonymous):

I have a question and I answered it by myself already would you mind checking it to see if im correct? @Hero

hero (hero):

Post it as a new question though.

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