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Mathematics 10 Online
OpenStudy (anonymous):

help please If P (A) = 0.2 and P (B) = 0.3 and A and B are independent but NOT disjoint, find P (A or B).

OpenStudy (anonymous):

is it .5?

OpenStudy (anonymous):

\[P(A\cup B)=P(A)+P(B)+P(A\cap B)\] If \(A\) and \(B\) are independent, then \(P(A\cap B)=P(A)P(B)\).

OpenStudy (anonymous):

So thats saying that p(A or B)= .2*.3?

OpenStudy (anonymous):

Right.

OpenStudy (anonymous):

oh ok Thank you very much :)

OpenStudy (anonymous):

yw

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