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OpenStudy (anonymous):
How would I get a parabola on a graph like this|dw:1401207668508:dw|
OpenStudy (anonymous):
@ganeshie8
OpenStudy (solomonzelman):
In ax^2+bx+c=0 if a is negative it opens down, just like you need. If a is positive then it is U shaped.
If it's zero it's not a parabola.
OpenStudy (solomonzelman):
do you need it at a specific center or anything like that ?
OpenStudy (anonymous):
yeah I need it at -3,5 for one and the other I need at 3,5
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OpenStudy (anonymous):
I have to make eyes for a clown and i can't use circles again @SolomonZelman
OpenStudy (solomonzelman):
Okay,
So parabola has a form of \(\Large\color{red}{ \bf y=a(x-h)^2+k }\)
choose any a that would determine how skinny or wide the parabola is (and if it is + or - if it is opening up or down)
OpenStudy (solomonzelman):
\(\Large\color{red}{ \bf 5=a(~~(-3)-h)^2+k }\)
OpenStudy (solomonzelman):
I would choose a=1 for positive (open ups) and a=-1 for negative (opens down)
OpenStudy (anonymous):
oh my gosh thank you!!!
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