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What is the axis of symmetry for the graph of the following function? y = -2(x + 4)^2 + 7 The axis of symmetry is x =
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@johnweldon1993
what makes the x part go to zero?
x+4 = 0 gives us the axis of symmetry
so x = 0?
lets chk ... does 0+4 = 0 ??? no
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no but 4 + -4=0
x + 4 = 0 when x=-4, therefore the axis of symmetry is x=-4
\[\large y = -2~\underbrace{(x + 4)}_{\text{helps define axis of symmetry}}~^2 + 7\]
yes
what do i need to do
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you might want to start at the top and read thru it ... the answer has already been given
-4
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