Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

Would someone help me? For some reason, I always get this one wrong /:

OpenStudy (anonymous):

ganeshie8 (ganeshie8):

what did u get ?

OpenStudy (anonymous):

12...

OpenStudy (anonymous):

Because there are two options for each question, right or wrong.

ganeshie8 (ganeshie8):

thats a very close guess :)

ganeshie8 (ganeshie8):

yes !!

ganeshie8 (ganeshie8):

the only mistake you're doing is adding, instead of multiplying

ganeshie8 (ganeshie8):

total possible outcomes = 2x2x2x2x2x2 = 2^6

OpenStudy (anonymous):

Ohh... So the answer is 64?

ganeshie8 (ganeshie8):

Yep !

OpenStudy (anonymous):

What about this one?

ganeshie8 (ganeshie8):

whats ur guess

OpenStudy (anonymous):

30, because 5*2*3.. but I feel it's wrong.

ganeshie8 (ganeshie8):

5 companies to choose from each has either ground/air shipping options(2) and they can be standard/express/overnight(3)

ganeshie8 (ganeshie8):

so total unique shipment options = 5*2*3 = 30

ganeshie8 (ganeshie8):

You're absolutely right !!

OpenStudy (anonymous):

Yay, thank you so much!

OpenStudy (anonymous):

Is the answer 12?

ganeshie8 (ganeshie8):

yw

OpenStudy (anonymous):

Is the answer 12 on the above question @ganeshie8 ?

ganeshie8 (ganeshie8):

how did u get 12

OpenStudy (anonymous):

3 places to fill 3 people.. 3^3 actually 27:) lol

ganeshie8 (ganeshie8):

good try, but no, there are indeed 7 people competing for 3 different roles right ?

OpenStudy (anonymous):

Oh yes..

ganeshie8 (ganeshie8):

So ?

OpenStudy (anonymous):

7^3= 343

OpenStudy (anonymous):

???

ganeshie8 (ganeshie8):

You're almost right !

ganeshie8 (ganeshie8):

Just keep in mind that these actors dont play double roles

ganeshie8 (ganeshie8):

So its something like this : there are 7 actors available for first role : 7 ways after that, there are only 6 actors available for second role : 6 ways after that, there are only 5 actors available for third role : 5 ways

OpenStudy (anonymous):

Yeah.. So.. 343 subtract something?

ganeshie8 (ganeshie8):

So, total number of unique arrangements = 7*6*5 = ?

OpenStudy (anonymous):

210!(:

OpenStudy (anonymous):

210:)

ganeshie8 (ganeshie8):

Yep!

OpenStudy (anonymous):

Am I right @ganeshie8 ?

ganeshie8 (ganeshie8):

Correct !

OpenStudy (hba):

Does the arrangement matter?

OpenStudy (anonymous):

Am I correct @ganeshie8 ?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!