WILL MEDAL FOR HELP!!! a cubical box with the dimensions 3 x 3 x 2 is melted into another cube whose width is 15. Find the length and height of the cube formed if l=h. formula for volume is w x l x h Width Length Height
I think you have to multiply the dimensions of the first box by 5. So 3*5, 3*5 and 2*5. So your dimensions are 15*15*10 and you multiply those together. So the length and height are 15 and 10. Im not sure if this is right though....
You need to find the volume of the first box. Wjhat will that be?
i don't think thats right. the volume has to stay the same.
and the volume would be 18
for the 1st one
Me? or nelsonjedi
@candy23456
well there isn't a whole lot of info
is there suppose to be a specific pattern to use?
OK now you have the volume of the first box is 18. We are melting it into a second box so the volume of the first box needs to equal the volume of the second box. How would you figure that out>
thats what i'm having trouble on. it would be 18= 15 x l x h but idk what to do next.
well 15 is the width and u cant really get 18 as the volume unless u use decimals maybe
or fractions as your 2 dimensions
i've tried dividing 18 by 15 but that didn't work right.
Jenn is right. Now we do we know about l and h for the second box?
try fractions or decimals
Divide both sides of the equation by 15 and what do you have?
15* 1/5*6???
1.2= l x h
i think i got it
yeah. but if you divide 1.2 by 2 you get .6 and if you then do the equation out it comes out as 5.4
when it should come out to 18
Sorry if l and h are equal the it would be the same as l^2 or h^2
yeah.
do i need the sqrt of 1.2 then?
l and h might be 1/3 and 6 unless there are no fractions wanted
No sqaure root of 1.2 works
Candy the problem states that l and h are equal
YAY!!! thanks guys so much! :)
Welsome :-)
where does it state that
it just say sto find l and h
it says find the length height of the cube formed if l=h
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