Which is the equation of the line passing through (0, 4) and (8, 0)? 1.y= -1/2x + 4 2.y= -1/2x + 8 3.y=-2x + 4 4.y=-2x + 9
Know how to find the slope using any two points?
well the slopes for 3. and 4. would be -2/1 right?
Yes. But I am saying, start with (0, 4) and (8, 0) and find the slope. Know how to do that?
\(\dfrac{\Delta y}{\Delta x}\) AKA: \(\dfrac{y_2-y_1}{x_2-x_1}\)
so 4/0 and 0/8 right?
No. If (0, 4) is \((x_1, y_1)\) and (8, 0) is \((x_2, y_2)\) what do you get when you substitude them into \(\dfrac{y_2-y_1}{x_2-x_1}\)? Ypu can copy and paste `\(\dfrac{y_2-y_1}{x_2-x_1}\)` if you want it formatted nice like what I type up. Or use (y_2-y_1)/(x_2-x_1) and replace them with the right numbers. Then you simplify.
(0-4)/(8-0)
-4/8? or 4/8
Right. Which becomes -4/8 and simplifies a bit more than that.
-1/2
so its either 1 or 2 now
Yes. So the slope, which is sometimes called m, is -1/2. OK, so next, you need to find the intercept. \(y=mx+b\) You know m, you need b. You have been given two points and found m. With that, do you think you can find b?
i forgot how to find b again haha
Pick one of the two points. Use the x and y from that point, as well as the m you just found, and plug them into \(y=mx+b\). See, \(y=mx+b\) has 4 variables. But you have 3 of the 4. Suddently you are able to solve for the remainging 1 when you plug in the other 3.
This is very typical in math. You use what is known to find what is unknown. You were given two points. You need \(y=mx+b\) form, so you need m and b. The two points let you find m. Then one point and m let you find b. Once you know m and b, then you can see the proper \(y=mx+b\) form that answers this question. It is just a set of steps. Each one is a small step. They build up as you do them. Eventually they make a solution.
hm
y=-1/2x +b im still confused on how to find b
Personally I like the first point because x is easy in that one.
so its y=-1/2x +4
Yep!
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