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Question based on Nature of roots
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If 2+i\[2+ i \sqrt{3}\] is a root of the equation x^2 + px + q = 0 where p ,q (belong to) rational numbers , then find the ordered pair (p,q)
\[\huge 2 + i \sqrt{3}\] is the root
then find p,q ?
yes
you know that if there is some complex root then the conjugate is also a root. So since this is a quadratic equation and you know one complex root, the missing one will be it's conjugate. Then use that p=-(1ºroot+2ºroot) and q=(1ºroot)(2ºroot)
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thank you
yw
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