Write the equation of the line that is parallel to the line y = -3x + 12 and passes through the point (-1, 6).

Question

anonymous · Answer

y = one thirdx + 7 

 y = -3x + 3 

 y = one thirdx + 3 

 y = -3x + 7

luigi0210 · Answer

Parallel, use the same slope: $m=-3$

Use the point slope formula: $\LARGE y-y_{1}=m(x-x_{1})$

anonymous · Answer

Where $$(x_1,y_1) $$ are your coordinates, and x and y are variables, solve for y.

anonymous · Answer

Aline  parallel to another line must have the same slope. The only difference can therefore be the y intercept of the line.
The slope of original line  =  -3
The equation of the parallel line is y = -3x +C where c is the intercept of the parallel line.
To find C we have a clue. The new line must pass through (-1, 6)
So the equation when we substitute for x and y becomes,
6 = -3 * -1  + C
C = 6 -3 = 2

So the parallel line equation is
y = -3x + 2

anonymous · Answer

Would it be B?