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on?
@d3v13
i dont understand how to solve it with the index...
16=2^4
54=2*(3^3)
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so we can write the whole equation as
\[3\times(2^{4/3}) + 3^{3/3}\times(2)^{1/3}\]
\[3\times2^{1/3}(2+1)\]
\[3^{2}\times2^{1/3}\]
why is it 3^2?
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3times3
=3times(2+1)
so thats the final answer?
yep
unless you want to use the calculator
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noo thank you hahaa im doing it online and its really complicated entering in the answer @d3v13
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