Help! Will fan and medal!
Q15, which one is linear?
Not sure, are you supposed to input values for the numbers to sort it out?
no, the linear function equation will have the formula y = mx + c, does this help? you should know what m and c are as we covered it earlier, right?
Ohh okay, Yeah I remember (: you've been a lot of help!
so which one is it her? b or c?
Give me a minute.. Sorry I'm slow Haha
B, right?
no, try again?
Shoot, so C... Hmm...
|dw:1401449874094:dw| b looks something like the above, this is not linear, you can see how the line bends at an angle, that's because of the modulus |x|
why wasn't C your first answer, what didnt you like about it? the fraction before x?
Yeah, and when I tried to put the numbers out for B., looked linear to me.
m in y=mx+c can be anything, a fraction is just fine, same applies to c in this equation
with Q 16 plot the values on the X-Y coordinates and if you get a straight line
thats one way of doing it, another way is to construct the euqation from 2 or more sets of points from the table and if you get y=mx+c then it is linear
Not quite, right?
Oh hang on my graph is a bit messed up haha
the distance on X and Y between your values isn't right
X is ok now, but Y is way out of whack
Oh yeah, my bad. Sorry, I've been up for over 24 hours lol one sec I'll sort it out
between 0 and 30 u have 1 unit, then same unit is used with 45, 50 ...
This should be sorted(:
yes and that's not linear
q 17 do the same, draw the graph and you'll see that it isnt linear
Right, so it's not linear because it doesn't form a straight line when the points are plotted. Does it need any more explanation than that do you think?
to be on the safe side use also this explanation the slope between the first 2 points is m = 15/100 and between the second 2 points it is m = 10/100 and between the third 2 points it is m = 5/100 in a linear function the m between any 2 points remains the same, here it is not so this is not a linear relation/function
Oh Okay, I am actually understanding this! thank you:)
am glad you can relate to it
Could you help me with this too? Sorry, I know I'm asking a lot, I can post a new thread if you fancy? (Just the top question)
yes please others will fancy that too
Alright, one moment (:
Join our real-time social learning platform and learn together with your friends!