Write an equation of a line parallel to y = 2 over 3x −5 in slope-intercept form that passes through the point (−6, −1).

Question

imstuck · Answer

This is weird.  In order to find the slope of the line you gave I graphed it on my calculator.  The slope is 5/8.  I couldn't figure out any other way to get that particular equation into a y = mx + b format.  Anyway, using the point-slope format, we get$$y+1=\frac{ 5 }{ 8 }(x+6)$$Distribute the 5/8 into the parenthesis and get$$y+1=\frac{ 5 }{ 8 }x+\frac{ 30 }{ 8 }$$Now subtract the 1 (in the form 8/8) from both sides.$$y=\frac{ 5 }{ 8 }x+\frac{ 30 }{ 8 }-\frac{ 8 }{ 8 }$$Simplifying gives you$$y=\frac{ 5 }{ 8 }x+\frac{ 22 }{ 8 }$$which reduces to $$y=\frac{ 5 }{ 8 }x+\frac{ 11 }{ 4 }$$That's the best I can do with that crazy first equation!!

anonymous · Answer

Thank You very much your a lifesaver