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Mathematics 12 Online
OpenStudy (anonymous):

Can someone check my answer? Find the equation for the graph. The equation I got is y=2x^2

OpenStudy (anonymous):

hartnn (hartnn):

in the graph, at x=1 y=4 thats not true according to your equation

hartnn (hartnn):

also, at x=0, y=2

hartnn (hartnn):

thats an exponentially growing function so try to make a function where exponent is 'x'

OpenStudy (anonymous):

oh ok. Could you show me step by step? I learn that way a lot easier.

hartnn (hartnn):

when x= 0, y=2 x=1, y= 4 x=2, y=8 ... x= -1, y=1

hartnn (hartnn):

that 2,4,8....sequence should remind you of \(2^n\) function

hartnn (hartnn):

but in that n starts from 1 here, when x=1, y =4 2^2 is 4 so exponent must be x+1 \(\Large 2^{x+1}\)

OpenStudy (anonymous):

oops I mean I got y=x^2

hartnn (hartnn):

no...thats not an exponential function either \(\large y= 2^{x+1}\)

OpenStudy (anonymous):

is y=2(2)^x an exponent?

OpenStudy (anonymous):

Sorry this is just confusing me haha.

hartnn (hartnn):

yes \(y = 2^{x+1} = 2 \times 2^x\)

OpenStudy (anonymous):

Oh ok! so y=2(2)^x is the answer?

hartnn (hartnn):

yup :)

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