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Mathematics 9 Online
OpenStudy (anonymous):

Write a vector equation and a scalar equation of the plane containing the lines: [x, y, z] = [-2, 3, 12] + s[-2, 1 , 5] and [x, y, z] = [1, -4, 4] + t[-6, 3, 15]

OpenStudy (loser66):

Woah.... I got the weird answer so that I dare not to say anything. let tag other @calculusxy @amistre64

OpenStudy (loser66):

@zepdrix @mathslover @whpalmer4

OpenStudy (loser66):

All are sleeping, Ok, let me try once Let L1 is line 1, the direction of the L1 (-2,1,5) L2 has direction (-6,3,15) We can see that L2 is a multiple of L1--> the plane containing those lines will have the normal vector (1, -3,1) I just take dot product of (-2,1,5) with \(\vec n (x, y, z)\) and choose (1,-3,1) we have normal vector have a line, we can write the equation of the plane, right? You can continue from here, right?

OpenStudy (anonymous):

Hey I really appeciate the help but I already closed this a while ago because I already figured it out. :P I did it a little differently though.

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