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Mathematics 15 Online
OpenStudy (anonymous):

please help

OpenStudy (anonymous):

(1,-4)

OpenStudy (anonymous):

Do you know what the function of that graph is? If you know the function you can find the vertex very easy

OpenStudy (anonymous):

not sure, but i think i have to use y = ax² and y = ax² + c

OpenStudy (anonymous):

well actually you have to use a more general formula than those, namely\[y=a(x-h)^2+k\]"a" is the slope, h is how far to the right you moved the graph left or right from it's original vertex of (0,0), and k is how far up or down you moved the graph from it's original point of (0,0)

OpenStudy (anonymous):

If all you want was to find the vertex, the easiest way to find a vertex is to look at the graph, and see which point the graph looks like it's coming from, like a starting point, the graph should then move outwards from that point

OpenStudy (anonymous):

ooh, thank you for explaining!

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