Question

the area of a rectangle is 65ft^2 and the length of the rectangle is double the width. find the dimensions

Answer 1

Okay I'm going to try and explain this to you as best as I can.

65=lw
that's your formula Area (65)= l(length) times w(width)
it says your length is 2 times the width.
let's name the width X
if this is the case then the length =2x
plug both those in the equation and you get
65= (x)(2x)
which simplified equals
65=3x
divide by 3 on both sides
65/3=3x/3
x= 21.6666...
you can round to whatever it asks for
Hope this helps!