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In the figure, ABC is an equilateral triangle. D,E and F are the mid-points of AB, BC and Ac respectively.
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\[How \to prove that, DF \parallel BC and DF = 1/2 BC ?\]
|dw:1401626335944:dw|
\[\Delta ABC =1/2 \Delta EDF, AB=1/2ED, AC=1/2EF \] AND so DF // to BC
|dw:1401627156750:dw|
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thanks for advice i know that
Yes, you know that, but the guy who asked to question apparently doesn't.
thnq!
yw
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