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If point D on the hill is 5 feet 6 inches above the base, B, of the pole, what is the shortest distance to the nearest inch, from D to the pole? Express your answer in feet and inches, such as 3 feet 10 inches. (Hint: Find tthe length of ED.) ___________
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To get this you need to find the distance ED = 5.6 tan 62° is roughly 10ft 4 inches
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|dw:1401652755593:dw|
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\(\tan 65^o = \dfrac{y}{x} \) \(y = x \tan 65^o\) \(y = (5 ~ft ~6 ~in.) \tan 65^o\) \(y = (5.5 ~ft) \tan 65^o\) \(y = 11.7948~ft\) \(y = 11~ft ~10~in.\)
@jjuden 1. 5 ft 6 in. is not 5.6 ft; it's 5 ft + 6/12 ft = 5.5 ft 2. The angle is 65 deg, not 62 deg.
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