Just found this question. It makes me feel like crap.
Alright, something looks like a Wheatstone bridge here. :)
@iambatman !!!
http://prntscr.com/3otn2w Found the solution to this. Can anyone explain how they reached here?
I feel your pain, the circuit gave me a headache. I fear I have over simplified by ignoring the two 25 Ohm resistors which appear to me to be in a balanced bridge (15/30 and 12/24), so this would be more or less a swag but I believe the resistance is 19.0 Ohms.
oh my GOODNESSS LOl
yup lol
Yup, erased those two already. Do I also combine the 30-30 and 24-24?
are we allowed to use calculator
id write huge matrices and just make the computer do it for me
I have a feeling that we are supposed to remove those diagonals too, since we're supposed to find the effective resistance between A and B, and those diagonals bring the current back from point B. This gives me 23.5 Ohms, but I'm not sure. Olympiads consider every little element of our thinking.
have you tried using Y delta transforms
No, I'd rather use normal methods.
First I'd figure out all the places with the same potentials
put a test source at a and b, and write nodal equations
There's also symmetry so...phew that makes it a bit easier.
Yes, I'm more interested in the solution exploiting symmetry.
Yeah I assumed so :P
I don't want to draw it out..but I'd draw it out first haha, so it looks better
|dw:1401757393324:dw| well you have to label all the stuff...lol, you can see though everything on the line with have the same potential.
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