What is the equation of the hyperbola shown below?

Question

anonymous · Answer

attachment

anonymous · Answer

@Shay17 ?

anonymous · Answer

You must want the wrong answer lol @ganeshie8 help !

jdoe0001 · Answer

any ideas on where the center is?

how long is the traverse axis?

how long is the conjugate axis?

anonymous · Answer

One vertex is at (a, 0), and the other is at (−a, 0) right?

jdoe0001 · Answer

is pretty much in the picture

traverse axis, distance from vertex to vertex, where the hyperbola takes off from

"a" component is  half that much
conjugate axis, distance from co-vertex to co-vertex, the ones the hyperbola doesn't touch
"b" component is  half that much

the hyperbola has a vertical traverse axis.. meaning the fraction with the "y" is the positive one, that is $\bf \cfrac{(y-k)^2}{a^2}-\cfrac{(x-h)^2}{b^2}=1$

jdoe0001 · Answer

and of course the center is at (h, k)